Social Anxiety Forums

Anonymous · Posted: Sun December 03, 2006 Post subject: 1 equals 2

a = b
a^2 = a*b
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)
(a+b) = b
a+a = a
2a = a
2 = 1

it's old i know but still awesome....
do u like it
post ur replies

Josh · Posted: Sun December 03, 2006 Post subject:

a^a is not the same as a*a

For example

2^3 = 8
2*3 = 6

However its good, you nearly got me.

Anonymous · Posted: Sun December 03, 2006 Post subject:

You have to define your variables uditbhargava.

It is ok josh, thats not the error in that equation. Sine a = b you can also say that it says a^2 = a*a. The problem is that you can't divide by zero. (a-b)

This one is better:

-1/1 = 1/-1
sq(-1/1) = sq(1/-1)
sq(-1)/sq(1) = sq(1)/sq(-1)
i/1 = 1/i
i/2 = 1/(2i)
i/2 + 3/(2i) = 1/(2i) + 3/(2i)
i(i/2 + 3/(2i)) = i(1/(2i) + 3/(2i))
i^2/2 + 3i/(2i) = i/(2i) + 3i/(2i)
-1/2 + 3/2 = 1/2 + 3/2
2/2 = 4/2
2 = 1

This should be way below your level of math josh. Good luck solving. Very Happy

Josh · Posted: Sun December 03, 2006 Post subject:

Yes its divide by zero error.

Josh · Posted: Sun December 03, 2006 Post subject:

I think the problem is in the square root.

sq(-1) = +/- i

EDIT: Actually I don't think that would make a difference.

OK I've got it the square root function SQRT(A*B) = SQRT(A)*SQRT(B) if A and B are both real.

Anonymous · Posted: Sun December 03, 2006 Post subject:

That be correct, and sq(1) = +/- 1 too.

Josh · Posted: Sun December 03, 2006 Post subject:

OK I've got it the square root function SQRT(A*B) = SQRT(A)*SQRT(B) if A and B are both real and greater than zero. Same with division.

Anonymous · Posted: Sun December 03, 2006 Post subject:

I never even thought of that part, good job.

Josh · Posted: Sun December 03, 2006 Post subject:

The you can't split up the square root unless both terms are positive.

Anonymous · Posted: Sun December 03, 2006 Post subject:

sq(1) = +/- 1 So that should be correct. Just a false root?

Josh · Posted: Sun December 03, 2006 Post subject:

No. The answer is that

This principle is only correct when y is a positive number.
http://en.wikipedia.org/wiki/Invalid_proof

sq(-1/1) = sq(1/-1)
sq(-1)/sq(1) = sq(1)/sq(-1)

This part is wrong. You can't split the squareroot up.

Anonymous · Posted: Sun December 03, 2006 Post subject:

This is confusing....

Anonymous · Posted: Sun December 03, 2006 Post subject:

I concur, thats true. However, if it wasn't you'd have to balance the formula out using multiple roots.

Hobo · Posted: Mon December 04, 2006 Post subject:

This must be a joke for smart people. I don't get it or want to get it.

Anonymous · Posted: Mon December 04, 2006 Post subject:

Your not the only one, this makes no sense at all. Very Happy